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bitblt Function in VB 2005Is there a way to use the windows bitblt function in a VB 2005 app? bitblt
requires device context parameters for the source and destination controls but those are not used in VB 2005. Is there some way around this? I have a program that uses a timer ... when it fires I want to copy a small block on the screen to a particular location. Thanks Have you checked the System.Drawing namespace ?
Basically .NET is about providing access to OS capabilities as a library of classes (that do not necessarily model the underlying API). For device context, try System.Drawing.Graphics... -- Show quoteHide quotePatrice "fripper" <yo***@indiana.edu> a écrit dans le message de news:ObGHWgvNGHA.1180@TK2MSFTNGP09.phx.gbl... > Is there a way to use the windows bitblt function in a VB 2005 app? bitblt > requires device context parameters for the source and destination controls > but those are not used in VB 2005. Is there some way around this? I have a > program that uses a timer ... when it fires I want to copy a small block on > the screen to a particular location. > > Thanks > > > "fripper" <yo***@indiana.edu> schrieb: If you cannot use the 'Graphics' object to blit the bitmap, you can use a > Is there a way to use the windows bitblt function in a VB 2005 app? > bitblt requires device context parameters for the source and destination > controls but those are not used in VB 2005. Is there some way around > this? I have a program that uses a timer ... when it fires I want to copy > a small block on the screen to a particular location. 'Graphics' object to get and release a device context handle (methods 'GetHdc', 'ReleaseHdc'). -- M S Herfried K. Wagner M V P <URL:http://dotnet.mvps.org/> V B <URL:http://classicvb.org/petition/> Here's a bit of code using bitblt and the Graphics object..should work in
2005 but don't know since I use 2003: Private Function CopyRect(ByVal Src As Graphics, ByVal RectF As Rectangle) As Bitmap 'Create Empty BitMap in Memory Dim srcBmp As New Bitmap(RectF.Width, RectF.Height, Src) Dim srcMem As Graphics = Graphics.FromImage(srcBmp) 'Get Device contexts for Source and Memory Graphics Objects Dim hdcSrc As IntPtr = Src.GetHdc Dim hdcMem As IntPtr = srcMem.GetHdc 'Get The Picture inside the Rectangle BitBlt(hdcMem, 0, 0, RectF.Width, RectF.Height, hdcSrc, RectF.X, RectF.Y, 13369376) 'Return Clone of the BitMap Dim rb As Bitmap = CType(srcBmp.Clone(), Bitmap) 'Clean Up Src.ReleaseHdc(hdcSrc) srcMem.ReleaseHdc(hdcMem) srcMem.Dispose() srcMem.Dispose() Return rb End Function -- Show quoteHide quoteDennis in Houston "fripper" wrote: > Is there a way to use the windows bitblt function in a VB 2005 app? bitblt > requires device context parameters for the source and destination controls > but those are not used in VB 2005. Is there some way around this? I have a > program that uses a timer ... when it fires I want to copy a small block on > the screen to a particular location. > > Thanks > > > >
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