I thought each Treeview node had a unique index in the nodes
collection but apparently I was wrong.

I'm pretty sure the VB6 Treeview had unique node indexs but I don't
want to set up an old computer with VB6 installed to check it.

Please try the following tree structure and tell me if I'm nuts:

Families
----Jones
--------James
------------Frank
----Smith
--------Willie
------------Bob
------------Lary

==================
1. Put a Treeview and a Listbox on a form.

2. Name the Treeview TV and paste the following code in the
appropriate events

3. Click the tree nodes and observe the index of each.

I understand that each node has its own nodes collection but is there
a unique identifier for every node? If so, how do you get it. Without
a unique index it seems to lead to some whacky results if you do the
following:

        tv.Nodes.Remove(tv.SelectedNode)

WHAT AM I MISSING?

    Thanks,

        Don

    Private Sub frmTest_Load(ByVal sender As System.Object, ByVal e As
System.EventArgs) Handles MyBase.Load

        Dim nod As TreeNode, wnod As TreeNode

        nod = tv.Nodes.Add("Families")
        nod = nod.Nodes.Add("Jones")
        nod = nod.Nodes.Add("James")
        nod = nod.Nodes.Add("Frank")
        nod.EnsureVisible()

        nod = tv.Nodes(0).Nodes.Add("Smith")
        wnod = nod.Nodes.Add("Willie")
        nod = wnod.Nodes.Add("Bob")
        nod = wnod.Nodes.Add("Larry")
        nod.EnsureVisible()

        nod = tv.Nodes(0).Nodes.Add("Johnson")
        nod.EnsureVisible()
        'tv.HideSelection = False
    End Sub


    Private Sub tv_AfterSelect(ByVal sender As System.Object, ByVal e
As System.Windows.Forms.TreeViewEventArgs) Handles tv.AfterSelect

        Dim n As TreeNode = tv.SelectedNode
        On Error Resume Next
        With ListBox1
            .Items.Clear()
            .Items.Add("Index: " & n.Index.ToString)
            .Items.Add("Text: " & n.Text)
            .Items.Add("Kids: " & n.GetNodeCount(True))
            .Items.Add("Parent: " & n.Parent.Index)
        End With
    End Sub

Show quote Hide quote I didn't test the code, but if you need to identify a node, store a
reference to the node.


Armin

In my example all nodes have an index of 0 except "Smith" and "Larry"
which each have an index of 1. Each sub tree seems to have its own 0
based indexing. The control must have been designed that way for some
purpose. My question is . . . what purpose and how/when would I make
use of it?

I'm a long time VB programmer who's been away from it for quite a
while and am trying to get my noggin around VB.Net. (I think this is
try #3) This treeview thing is one of many that's befuddling me.

I feel like one of those natives in the movies that see a cigarette
lighter for the first time. Mundane if you're hip but magic if you're
not. I'm, aparantly, not.   :(

Thanks,

    Don


On Sat, 4 Mar 2006 02:55:45 +0100, "Armin Zingler"
<az.nospam@freenet.de> wrote:

Show quoteHide quote

I should have tested it... I'm gonna do that now.


Armin

Show quote Hide quote Well, I tested it now, but everything works as expected. Each node has it's
sub nodes. They are stored in a collection. The index is the index within
this collection. For example, you can use the index to persistently store a
reference to a node outside the application, like storing "2,0,1" in a file
to store the user's selection when the program quits and restore it at
restart. So, I don't see a problem - or I didn't get the point.



Armin

Hi Armin,

So, you're saying that the only intrinsic way to address a node is
through "relative addressing". It appears that is apparently true but
seems very inelegant and messy. At least it seems that way to me.

Thank you for your help.

    Don


On Sat, 4 Mar 2006 12:15:40 +0100, "Armin Zingler"
<az.nospam@freenet.de> wrote:

Show quoteHide quote

The other way to address a node is to store the reference.


Armin

I've extended the treenode class to add some new properties. It seems
to work well.  I'm also  thinking about trying to extend the nodes
collection. This is my first attempt and am wondering if you have any
suggestions or potential gotcha's I might prepare for.

Thank you again,

    Don

On Sat, 4 Mar 2006 21:45:39 +0100, "Armin Zingler"
<az.nospam@freenet.de> wrote:

Show quoteHide quote

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