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actual recordHow obtain the current record ? this is my code:
Dim fila As DataRow Dim llaveprimaria(0) As DataColumn llaveprimaria(0) = dasedo.Tables("tabest").Columns("codigo") dasedo.Tables("tabest").PrimaryKey() = llaveprimaria fila = dasedo.Tables("tabest").Rows.Find(c_idfind) Me.BindingContext(dasedo, "tabest").Position = 1 (bad code line help me please) Jose,
Have a look at this sample where your problem is done. There is as well your next problem in it. http://www.vb-tips.com/default.aspx?ID=c4832a2a-2b95-4ded-93d9-4deb7fa4a0b8 I hope this helps, Cor Show quoteHide quote "Jose" <josenospam@unica.com> schreef in bericht news:e2CDO7JdGHA.3952@TK2MSFTNGP04.phx.gbl... > How obtain the current record ? this is my code: > > Dim fila As DataRow > > Dim llaveprimaria(0) As DataColumn > > llaveprimaria(0) = dasedo.Tables("tabest").Columns("codigo") > > dasedo.Tables("tabest").PrimaryKey() = llaveprimaria > > fila = dasedo.Tables("tabest").Rows.Find(c_idfind) > > Me.BindingContext(dasedo, "tabest").Position = 1 (bad code line help me > please) > > Cor this link has problems? I don´t access.
Show quoteHide quote "Cor Ligthert [MVP]" <notmyfirstn***@planet.nl> escribió en el mensaje news:eoC4C9MdGHA.1324@TK2MSFTNGP04.phx.gbl... > Jose, > > Have a look at this sample where your problem is done. > > There is as well your next problem in it. > > http://www.vb-tips.com/default.aspx?ID=c4832a2a-2b95-4ded-93d9-4deb7fa4a0b8 > > > I hope this helps, > > Cor > > "Jose" <josenospam@unica.com> schreef in bericht > news:e2CDO7JdGHA.3952@TK2MSFTNGP04.phx.gbl... >> How obtain the current record ? this is my code: >> >> Dim fila As DataRow >> >> Dim llaveprimaria(0) As DataColumn >> >> llaveprimaria(0) = dasedo.Tables("tabest").Columns("codigo") >> >> dasedo.Tables("tabest").PrimaryKey() = llaveprimaria >> >> fila = dasedo.Tables("tabest").Rows.Find(c_idfind) >> >> Me.BindingContext(dasedo, "tabest").Position = 1 (bad code line help me >> please) >> >> > > Jose,
We are changing thanks for telling this to us. Here the tip as it is there. \\\\ Controls Databinding (Textbox), given is here a kind of standard routine for a textbox and a datatable datetime column, the sample needs only a form with a textbox and two buttons dragged on it (The sample is based on VB2005 style. For VB2002/2003 you have remove the Import, the Public Class Form1 and the End Class and paste it than in) -------------------------------------------------------------------------------- Imports System.data Public Class Form1 Dim ds As New DataSet Private Sub Form1_Load(ByVal sender As System.Object, _ ByVal e As System.EventArgs) Handles MyBase.Load Dim dt As New DataTable ds.Tables.Add(dt) dt.Columns.Add("DateField", GetType(System.DateTime)) Dim Mybinding As New Binding("Text", ds.Tables(0), "DateField") TextBox1.DataBindings.Add(Mybinding) AddHandler Mybinding.Format, AddressOf DBdateTextbox AddHandler Mybinding.Parse, AddressOf TextBoxDBdate dt.LoadDataRow(New Object() {New DateTime(2005, 8, 4)}, True) dt.LoadDataRow(New Object() {Nothing}, True) dt.LoadDataRow(New Object() {New DateTime(2005, 8, 5)}, True) End Sub Private Sub Button1_Click(ByVal sender As System.Object, _ ByVal e As System.EventArgs) Handles Button1.Click 'forward If BindingContext(ds.Tables(0)).Position _ < ds.Tables(0).Rows.Count Then BindingContext(ds.Tables(0)).Position += 1 End If End Sub Private Sub Button2_Click(ByVal sender As System.Object, _ ByVal e As System.EventArgs) Handles Button2.Click 'backward If BindingContext(ds.Tables(0)).Position > 0 Then BindingContext(ds.Tables(0)).Position -= 1 End If End Sub Private Sub DBdateTextbox(ByVal sender As Object, _ ByVal cevent As ConvertEventArgs) If cevent.Value Is DBNull.Value Then cevent.Value = "" Else Dim datum As Date datum = CDate(cevent.Value) cevent.Value = datum.ToString("d") End If End Sub Private Sub TextBoxDBdate(ByVal sender As Object, _ ByVal cevent As ConvertEventArgs) If cevent.Value.ToString = "" Then cevent.Value = DBNull.Value Else Dim datum As Date datum = CDate(cevent.Value) cevent.Value = datum End If End Sub End Class I hope this helps, cor Show quoteHide quote "Jose" <josenospam@unica.com> schreef in bericht news:%23zDSInOdGHA.1320@TK2MSFTNGP04.phx.gbl... > Cor this link has problems? I don´t access. > > > "Cor Ligthert [MVP]" <notmyfirstn***@planet.nl> escribió en el mensaje > news:eoC4C9MdGHA.1324@TK2MSFTNGP04.phx.gbl... >> Jose, >> >> Have a look at this sample where your problem is done. >> >> There is as well your next problem in it. >> >> http://www.vb-tips.com/default.aspx?ID=c4832a2a-2b95-4ded-93d9-4deb7fa4a0b8 >> >> >> I hope this helps, >> >> Cor >> >> "Jose" <josenospam@unica.com> schreef in bericht >> news:e2CDO7JdGHA.3952@TK2MSFTNGP04.phx.gbl... >>> How obtain the current record ? this is my code: >>> >>> Dim fila As DataRow >>> >>> Dim llaveprimaria(0) As DataColumn >>> >>> llaveprimaria(0) = dasedo.Tables("tabest").Columns("codigo") >>> >>> dasedo.Tables("tabest").PrimaryKey() = llaveprimaria >>> >>> fila = dasedo.Tables("tabest").Rows.Find(c_idfind) >>> >>> Me.BindingContext(dasedo, "tabest").Position = 1 (bad code line help me >>> please) >>> >>> >> >> > > Jose,
Please don't start new threads about the same question. This is not a 10 second answer newsgroup. Thanks in advance. Cor Show quoteHide quote "Jose" <josenospam@unica.com> schreef in bericht news:e2CDO7JdGHA.3952@TK2MSFTNGP04.phx.gbl... > How obtain the current record ? this is my code: > > Dim fila As DataRow > > Dim llaveprimaria(0) As DataColumn > > llaveprimaria(0) = dasedo.Tables("tabest").Columns("codigo") > > dasedo.Tables("tabest").PrimaryKey() = llaveprimaria > > fila = dasedo.Tables("tabest").Rows.Find(c_idfind) > > Me.BindingContext(dasedo, "tabest").Position = 1 (bad code line help me > please) > > |
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