Exists a function that determined between two dates the years,months and
days?

Thanks a lot.

dim x as date  = someDate.subtract(someOtherDate)

Then format x as desired.



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Scott M. wrote:
The Subtract method on the DateTime structure, when passed another
DateTime, returns a Timespan object and not a DateTime object.

Dim ts As TimeSpan = someDate.Subtract(someOtherDate)

Then you can get the years, months, and days properties from the
TimeSpan.

Chris Dunaway wrote:
Actually, you can only get the value as days.

As the timespan doesn't contain a starting and ending time, there is no
way to determine the exact length in months and years.

or you could use a real function like DateDiff right?

who the hell changes a function like DateDiff??

-Aaron


Göran Andersson wrote:
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Göran Andersson wrote:
I stand corrected.  But when you subtract a date from another date, it
returns a Timespan and not a date.

Chris Dunaway wrote:
Yes. If you read my next sentence you see that I am referring to the
TimeSpan structure. That implies that I concur with your observation. :)

Göran Andersson wrote:
My mistake, I was actually replying to Scott M.'s message.

Jose,

In my idea does this never work as measuring system. Somehow I thought it is
not possible with the Gregorian Calender, every month can have a different
length you know, not to talk about leap years. Therefore it is not such a
good measuring system.

Therefore
Date - Date represented as year, months, will  will give a total other
result in by instance days as you use another startdate and add your
measured result.

(Years, weeks, days) or (years, days) will do a better job.
Although the leap year problem sustains..

That is the reason that some people want to use this kind of calendars.

http://en.wikipedia.org/wiki/Positivist_Calendar

But just my thought.

Cor

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