[Regular Expression] match word with interpunctuation

Hallo,
I need to build a regular expression
able to match a specified word,
preceded and followed by few chars (mainly interpunctuation)
Below the code.

------------------------

Explanation:

let's assume the word is
baby
these are the 27 cases I need to match:



baby         baby is simply standing alone (obviously)



and also these cases:



baby.
baby,
baby;
baby:
baby!
baby?
baby       baby with a following blank space
baby-
baby"
baby'
baby\
baby/
baby)



and also these cases:


..Baby
,baby
;baby
baby      baby with a preceding blank space
-baby
"baby
'baby
\baby
/baby
(baby



and also
the resulting regexp
must exclude the following cases:


babylon     baby followed by any char
lonbaby     baby preceded by any char
baby678    baby followed by any number
678baby    baby precede  by any number



-------------------

This is the code:
'I have to count all the the occurences in a long text.
'I tried this code, but it didn't work:



Dim myCounter As Integer = 0

Dim myMatch As Match = Nothing

Dim myLongText As String = "This morning ...blah...blah.... goodnight to
everyone"

Dim myPattern As String = "[.;:/,-"!\?'( ]" & "baby" & "[.;:/,-"!\?') ]"




myMatch = Regex.Match(myLongText, myPattern, RegexOptions.Multiline Or
RegexOptions.IgnoreCase)


Do While myMatch.Success
    myCounter = myCounter + 1
    myMatch  = myMatch.NextMatch
Loop



Debug.Write (myCounter.tostring)

On Tue, 27 Jun 2006 01:58:22 +0200, teo <t**@inwind.it> wrote:
Show quoteHide quoteDoes it specificaly have to be that punctuation or can it be any
non-alphanumeric character?

If so, some thing like:
"\b" & word &  "\b" should work.

See "regular expressions, atomic zero-width assertions" in the help.

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