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Removing multiple items from a multi-select ListViewWhat's the correct way to remove multiple, selected items from a ListView control (say, from a ContextMenu)? I ask because I'm getting a very annoying ArgumentOutOfRangeException because the ListView seems to be trying to "re-select" items that are no longer there! for example, giventhat I have 3 items in my list: Select the first and remove it - no problem. Select the last /but one/ and remove it - still no problem. Select the /last/ item and remove it - Boom! ArgumentOutOfRangeException Parameter name: '2' is not a valid value for 'displayIndex' at S.W.F.ListViewItemCollection.getItem(Int32 displayIndex) at S.W.F.ListView.LvnBeginDrag(MouseButtons buttons, NMLISTVIEW mnlv) ... It's as if the "list" of select indices is being re-applied, even though the items to which those items correspond[ed] have been removed. Any suggestions? [Code] Dim iIndices As Integer() ReDim iIndices(Me.lvMembers.SelectedIndices.Count - 1) Me.lvMembers.SelectedIndices.CopyTo(iIndices, 0) For iIndex As Integer = iIndices.Length - 1 To 0 Step -1 Dim oItem As ListViewItem _ = Me.lvMembers.Items(iIndices(iIndex)) oItem.Selected = False ' even tried this! Me.lvMembers.Items.Remove(oItem) Next TIA, Phill W. Why do you select the item to remove it
Get the index of the item you want to remove and use the ListView.Items.RemoveAt method hth, Samuel Show quoteHide quote "Phill W." <p-.-a-.-w-a-r-d@o-p-e-n-.-a-c-.-u-k> wrote in message news:eaadhl$4ga$1@south.jnrs.ja.net... > (VB'2003) > What's the correct way to remove multiple, selected items from a ListView > control (say, from a ContextMenu)? > > I ask because I'm getting a very annoying ArgumentOutOfRangeException > because the ListView seems to be trying to "re-select" items that are no > longer there! > > for example, giventhat I have 3 items in my list: > Select the first and remove it - no problem. > Select the last /but one/ and remove it - still no problem. > Select the /last/ item and remove it - Boom! > > ArgumentOutOfRangeException > Parameter name: '2' is not a valid value for 'displayIndex' > at S.W.F.ListViewItemCollection.getItem(Int32 displayIndex) > at S.W.F.ListView.LvnBeginDrag(MouseButtons buttons, NMLISTVIEW mnlv) > ... > > It's as if the "list" of select indices is being re-applied, even though > the items to which those items correspond[ed] have been removed. > > Any suggestions? > > [Code] > Dim iIndices As Integer() > ReDim iIndices(Me.lvMembers.SelectedIndices.Count - 1) > Me.lvMembers.SelectedIndices.CopyTo(iIndices, 0) > > For iIndex As Integer = iIndices.Length - 1 To 0 Step -1 > Dim oItem As ListViewItem _ > = Me.lvMembers.Items(iIndices(iIndex)) > > oItem.Selected = False ' even tried this! > Me.lvMembers.Items.Remove(oItem) > Next > > TIA, > Phill W. Samuel,
> Why do you select the item to remove it I don't - I'm trying to "un-select" it in the vain hope that the ListView control won't then try to redisplay it in a "selected" way (or /any/ way, come to that), which is what's causing it to blow up. > Get the index of the item you want to remove and use the Yep - tried that. Same results using Remove(item) and RemoveAt(index).> ListView.Items.RemoveAt method Regards, Phill W. Samuel Shulman wrote: Show quoteHide quote > Why do you select the item to remove it > Get the index of the item you want to remove and use the > ListView.Items.RemoveAt method > > hth, > Samuel > > "Phill W." <p-.-a-.-w-a-r-d@o-p-e-n-.-a-c-.-u-k> wrote in message > news:eaadhl$4ga$1@south.jnrs.ja.net... >> (VB'2003) >> What's the correct way to remove multiple, selected items from a ListView >> control (say, from a ContextMenu)? >> >> I ask because I'm getting a very annoying ArgumentOutOfRangeException >> because the ListView seems to be trying to "re-select" items that are no >> longer there! >> >> for example, giventhat I have 3 items in my list: >> Select the first and remove it - no problem. >> Select the last /but one/ and remove it - still no problem. >> Select the /last/ item and remove it - Boom! >> >> ArgumentOutOfRangeException >> Parameter name: '2' is not a valid value for 'displayIndex' >> at S.W.F.ListViewItemCollection.getItem(Int32 displayIndex) >> at S.W.F.ListView.LvnBeginDrag(MouseButtons buttons, NMLISTVIEW mnlv) >> ... >> >> It's as if the "list" of select indices is being re-applied, even though >> the items to which those items correspond[ed] have been removed. >> >> Any suggestions? >> >> [Code] >> Dim iIndices As Integer() >> ReDim iIndices(Me.lvMembers.SelectedIndices.Count - 1) >> Me.lvMembers.SelectedIndices.CopyTo(iIndices, 0) >> >> For iIndex As Integer = iIndices.Length - 1 To 0 Step -1 >> Dim oItem As ListViewItem _ >> = Me.lvMembers.Items(iIndices(iIndex)) >> >> oItem.Selected = False ' even tried this! >> Me.lvMembers.Items.Remove(oItem) >> Next >> >> TIA, >> Phill W. > > Maybe that,
When you actually remove an item then the index of the other items changes and if say the maximum index value was 10 after removing any item it will be 9 You can do 1 of the following: 1. Record to some variables (array) a unique value of the items you want to remove and find out the index of that item each time based on that value then usse the removeAt 2. Reference all the items to remove to a created array of items then loop through this array (I hope that the valuue of the index will change as you go along) hth, Samuel Shulman Show quoteHide quote "Phill W." <p-.-a-.-w-a-r-d@o-p-e-n-.-a-c-.-u-k> wrote in message news:eaalaa$6pr$2@south.jnrs.ja.net... > Samuel, > > > Why do you select the item to remove it > I don't - I'm trying to "un-select" it in the vain hope that the ListView > control won't then try to redisplay it in a "selected" way (or /any/ way, > come to that), which is what's causing it to blow up. > > > Get the index of the item you want to remove and use the > > ListView.Items.RemoveAt method > > Yep - tried that. Same results using Remove(item) and RemoveAt(index). > > Regards, > Phill W. > > Samuel Shulman wrote: >> Why do you select the item to remove it >> Get the index of the item you want to remove and use the >> ListView.Items.RemoveAt method >> >> hth, >> Samuel >> >> "Phill W." <p-.-a-.-w-a-r-d@o-p-e-n-.-a-c-.-u-k> wrote in message >> news:eaadhl$4ga$1@south.jnrs.ja.net... >>> (VB'2003) >>> What's the correct way to remove multiple, selected items from a >>> ListView control (say, from a ContextMenu)? >>> >>> I ask because I'm getting a very annoying ArgumentOutOfRangeException >>> because the ListView seems to be trying to "re-select" items that are no >>> longer there! >>> >>> for example, giventhat I have 3 items in my list: >>> Select the first and remove it - no problem. >>> Select the last /but one/ and remove it - still no problem. >>> Select the /last/ item and remove it - Boom! >>> >>> ArgumentOutOfRangeException >>> Parameter name: '2' is not a valid value for 'displayIndex' >>> at S.W.F.ListViewItemCollection.getItem(Int32 displayIndex) >>> at S.W.F.ListView.LvnBeginDrag(MouseButtons buttons, NMLISTVIEW mnlv) >>> ... >>> >>> It's as if the "list" of select indices is being re-applied, even though >>> the items to which those items correspond[ed] have been removed. >>> >>> Any suggestions? >>> >>> [Code] >>> Dim iIndices As Integer() >>> ReDim iIndices(Me.lvMembers.SelectedIndices.Count - 1) >>> Me.lvMembers.SelectedIndices.CopyTo(iIndices, 0) >>> >>> For iIndex As Integer = iIndices.Length - 1 To 0 Step -1 >>> Dim oItem As ListViewItem _ >>> = Me.lvMembers.Items(iIndices(iIndex)) >>> >>> oItem.Selected = False ' even tried this! >>> Me.lvMembers.Items.Remove(oItem) >>> Next >>> >>> TIA, >>> Phill W. >> Samuel,
Found it! Old habits die hard: I was displaying the Context Menu manually (using ContextMenu.Show) but from the ListView's Mouse/Down/ event instead of Mouse/Up/. Moved my code into [ListView].MouseUp and everything works as expected! Regards, Phill W. Samuel Shulman wrote: Show quoteHide quote > Maybe that, > When you actually remove an item then the index of the other items changes > and if say the maximum index value was 10 after removing any item it will be > 9 > > You can do 1 of the following: > 1. Record to some variables (array) a unique value of the items you want to > remove and find out the index of that item each time based on that value > then usse the removeAt > > 2. Reference all the items to remove to a created array of items then loop > through this array (I hope that the valuue of the index will change as you > go along) > > > hth, > Samuel Shulman > > > > "Phill W." <p-.-a-.-w-a-r-d@o-p-e-n-.-a-c-.-u-k> wrote in message > news:eaalaa$6pr$2@south.jnrs.ja.net... >> Samuel, >> >>> Why do you select the item to remove it >> I don't - I'm trying to "un-select" it in the vain hope that the ListView >> control won't then try to redisplay it in a "selected" way (or /any/ way, >> come to that), which is what's causing it to blow up. >> >>> Get the index of the item you want to remove and use the >>> ListView.Items.RemoveAt method >> Yep - tried that. Same results using Remove(item) and RemoveAt(index). >> >> Regards, >> Phill W. >> >> Samuel Shulman wrote: >>> Why do you select the item to remove it >>> Get the index of the item you want to remove and use the >>> ListView.Items.RemoveAt method >>> >>> hth, >>> Samuel >>> >>> "Phill W." <p-.-a-.-w-a-r-d@o-p-e-n-.-a-c-.-u-k> wrote in message >>> news:eaadhl$4ga$1@south.jnrs.ja.net... >>>> (VB'2003) >>>> What's the correct way to remove multiple, selected items from a >>>> ListView control (say, from a ContextMenu)? >>>> >>>> I ask because I'm getting a very annoying ArgumentOutOfRangeException >>>> because the ListView seems to be trying to "re-select" items that are no >>>> longer there! >>>> >>>> for example, giventhat I have 3 items in my list: >>>> Select the first and remove it - no problem. >>>> Select the last /but one/ and remove it - still no problem. >>>> Select the /last/ item and remove it - Boom! >>>> >>>> ArgumentOutOfRangeException >>>> Parameter name: '2' is not a valid value for 'displayIndex' >>>> at S.W.F.ListViewItemCollection.getItem(Int32 displayIndex) >>>> at S.W.F.ListView.LvnBeginDrag(MouseButtons buttons, NMLISTVIEW mnlv) >>>> ... >>>> >>>> It's as if the "list" of select indices is being re-applied, even though >>>> the items to which those items correspond[ed] have been removed. >>>> >>>> Any suggestions? >>>> >>>> [Code] >>>> Dim iIndices As Integer() >>>> ReDim iIndices(Me.lvMembers.SelectedIndices.Count - 1) >>>> Me.lvMembers.SelectedIndices.CopyTo(iIndices, 0) >>>> >>>> For iIndex As Integer = iIndices.Length - 1 To 0 Step -1 >>>> Dim oItem As ListViewItem _ >>>> = Me.lvMembers.Items(iIndices(iIndex)) >>>> >>>> oItem.Selected = False ' even tried this! >>>> Me.lvMembers.Items.Remove(oItem) >>>> Next >>>> >>>> TIA, >>>> Phill W. > Phill W. wrote:
Show quoteHide quote > (VB'2003) At the risk of seeming to talk to myself (not a first, by any means) it > What's the correct way to remove multiple, selected items from a > ListView control (say, from a ContextMenu)? > > I ask because I'm getting a very annoying ArgumentOutOfRangeException > because the ListView seems to be trying to "re-select" items that are no > longer there! > > for example, giventhat I have 3 items in my list: > Select the first and remove it - no problem. > Select the last /but one/ and remove it - still no problem. > Select the /last/ item and remove it - Boom! > > ArgumentOutOfRangeException > Parameter name: '2' is not a valid value for 'displayIndex' > at S.W.F.ListViewItemCollection.getItem(Int32 displayIndex) > at S.W.F.ListView.LvnBeginDrag(MouseButtons buttons, NMLISTVIEW mnlv) > ... > > It's as if the "list" of select indices is being re-applied, even though > the items to which those items correspond[ed] have been removed. > > Any suggestions? > > [Code] > Dim iIndices As Integer() > ReDim iIndices(Me.lvMembers.SelectedIndices.Count - 1) > Me.lvMembers.SelectedIndices.CopyTo(iIndices, 0) > > For iIndex As Integer = iIndices.Length - 1 To 0 Step -1 > Dim oItem As ListViewItem _ > = Me.lvMembers.Items(iIndices(iIndex)) > > oItem.Selected = False ' even tried this! > Me.lvMembers.Items.Remove(oItem) > Next > > TIA, > Phill W. looks like the SelectedIndices might be a Red Herring. I /only/ get this problem if the item corresponding to the last item I selected (by Clicking and Ctrl-Clicking in the ListView) is removed, so... If I select the last item in the list, then the first, I can remove them both and the first item remains selected. If I select the first item, then the last, and remove them - Boom! Regards, Phill W. 
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