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Challenging PRoblem in VB.NET.User = 'Hisouka' Password = '1234' HEre is my Table in SQL Server Tablename: TABLESAMP Field1 Field2 Field3 abs NULL PRIMARY aaa aaa Primary 1.1 zzz bbb Primary 1.2 bbb 1234 SECONDARY ccc zzz Secondary 1.1 ddd abs Secondary 1.2 If Record in Field2 is not exist in column Field1 then the Record in Field3 must be a root node If Record in Field2 is exist in Field1 then the Record in Field3 must be a sub node of last root node Possible list on my Tree View: PRIMARY Primary 1.1 Primary 1.2 SECONDARY Secondary 1.1 Seconday 1.2 Can anyone give me possible Code? including SQL Connection.. Thanks Aprreciation if solved.. Here's a website for connecting via ADO or ADO.NET using both VB and
C#. You may also dig up some info on the SQLConnection and transaction objects, as they are optimized for SQL server. http://support.sas.com/ctx/samples/index.jsp?sid=817 Use www.connectionstrings.com to get the appropriate connection string. The simplist (and not the most efficient) is to pull the table into a datareader, and start looping through it. Do your comparison in the loop and add the root and child nodes depending on the results of your comparison. Thanks, Seth Rowe Hisouka wrote: Show quoteHide quote > DBase = 'MYDB' > User = 'Hisouka' > Password = '1234' > > HEre is my Table in SQL Server > > > Tablename: TABLESAMP > > > Field1 Field2 Field3 > abs NULL PRIMARY > aaa aaa Primary 1.1 > zzz bbb Primary 1.2 > bbb 1234 SECONDARY > ccc zzz Secondary 1.1 > ddd abs Secondary 1.2 > > > If Record in Field2 is not exist in column Field1 then the Record in > Field3 must be a root node > If Record in Field2 is exist in Field1 then the Record in Field3 must > be a sub node of last root node > > > Possible list on my Tree View: > > > PRIMARY > Primary 1.1 > Primary 1.2 > SECONDARY > Secondary 1.1 > Seconday 1.2 > > > Can anyone give me possible Code? including SQL Connection.. > > > Thanks > Aprreciation if solved..
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> Hi,> Possible list on my Tree View: > > > PRIMARY > Primary 1.1 > Primary 1.2 > SECONDARY > Secondary 1.1 > Seconday 1.2 > > > Can anyone give me possible Code? including SQL Connection.. > > It seems from what I see above, that you are attempting to solve one of those non-trivial problems in CS, i.e. storing and manipulating a tree structure in a database. The problem with hard coding rules is that the number increases exponentially with the level or "depth" of the tree. In your example you have two levels, which is fairly trivial, but might you want to expand to 4, 8 or "n" levels in future? If that is the case, you need to write some serious plumbing (preferably in stored procedures) to implement a generalized tree structure. There are a few solutions that spring to mind that you could research. Celko has written widely on this subject (google: Celko+Tree Structure In Database). The method I personally prefer however involves storing a Parent ID and Path String with each "node" (record) in my database. By doing this it's possible to select sub-trees using the "LIKE" predicate. Building a tree from a set of records is quite simple if you can get the records back in tree order (order by "Path" ASC). If you would like further information on how to do this, I might be able to provide some, having scratched my head over this problem during the last three years of my work-life ;). Robin
Whats the right approach for getting a job
Copy Directory Simulate Autoredraw Can forms in different projects reference one another? Transparent attribute for labels Convert Now to a string VB Guru please explain me how this can work ? split container variable value becoming null class and component class |
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